Re: Expected value of the Geometric distribution
- To: mathgroup at smc.vnet.net
- Subject: [mg118483] Re: Expected value of the Geometric distribution
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Fri, 29 Apr 2011 07:33:38 -0400 (EDT)
The geometric distribution is discrete (of course), so... Sum[(1 - p)^k*p*k, {k, 1, Infinity}] (1 - p)/p Bobby On Thu, 28 Apr 2011 05:37:38 -0500, Tonja Krueger <tonja.krueger at web.de> wrote: > Hi all, > I want to calculate expected value of diverse distributions like the > Geometric distribution (for example). > As I understand this, the expected value is the integral of the density > function *x. > But when I try to calculate this: > Integrate[(1-p)^k*p*k,k] > I get this as the answer: > ((1 - p)^k p (-1 + k Log[1 - p]))/Log[1 - p]^2 > Instead of: (1-p)/p. > I would be so grateful if someone could explain to me what I'm doing > wrong. > Tonja > ___________________________________________________________ > Empfehlen Sie WEB.DE DSL Ihren Freunden und Bekannten und wir > belohnen Sie mit bis zu 50,- Euro! https://freundschaftswerbung.web.de > -- DrMajorBob at yahoo.com