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Re: Expected value of the Geometric distribution

  • To: mathgroup at smc.vnet.net
  • Subject: [mg118464] Re: Expected value of the Geometric distribution
  • From: Gary Wardall <gwardall at gmail.com>
  • Date: Fri, 29 Apr 2011 07:30:12 -0400 (EDT)
  • References: <ipbg1f$ahf$1@smc.vnet.net>

On Apr 28, 5:37 am, "Tonja Krueger" <tonja.krue... at web.de> wrote:
> Hi all,
> I want to calculate expected value of diverse distributions like the Geometric distribution (for example).
> As I understand this, the expected value is the integral of the density function *x.
> But when I try to calculate this:
> Integrate[(1-p)^k*p*k,k]
> I get this as the answer:
> ((1 - p)^k p (-1 + k Log[1 - p]))/Log[1 - p]^2
> Instead of: (1-p)/p.
> I would be so grateful if someone could explain to me what I'm doing wrong.
> Tonja
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Tonia,

I think the Geometric Distribution is discrete, in which case you
should use the Sum[  command.

Note:

Sum[(1 - p)^k*p*k, {k, 1, Infinity}]

Yields:

(1 - p)/p

Good Luck

Gary Wardall


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