Integrate this how?
- To: mathgroup at smc.vnet.net
- Subject: [mg116294] Integrate this how?
- From: BoLe <bole79 at gmail.com>
- Date: Thu, 10 Feb 2011 05:21:36 -0500 (EST)
Curve is closed (t from -Pi to Pi) and in polar form
r[t_]:=(1+Sin[t]) (1+9/10 Cos[8 t]) (1+1/10 Cos[24 t]) (9/10+5/100
Would like to find out its arc length, so the integral of
Version 7 complains but returns a somewhat reasonable number
(something around 50; drew together with a circle of the same length),
version 8 says nothing but gives just too low a number (five and
something). How can this be? New Mathematica should have no problem
with such high oscillatory integrands, shouldn't she?
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