Re: From Reduce to List

```I think the only exceptions are non-generic cases like this one:

{Reduce[a x == 0, x] // ToRules}

{{a->0},{x->0}}

Solve[a x == 0, x]

{{x->0}}

Andrzej Kozlowski

On 24 Jul 2011, at 12:38, Fred Simons wrote:

> In[8]:=
> expr=(a==1001&&b==1001000)||(a==1002&&b==501000)||(a==1004&&b==251000);
> {a,b}/.{ToRules[expr]}
>
> Out[9]= {{1001,1001000},{1002,501000},{1004,251000}}
>
> If expr is indeed the result of a Reduce command, I think it is very
> likely that instead of Reduce you could have used Solve (it has quite a
> lot of new features) in order to obtain the rules immediately.
>
> Kind regards,
>
> Fred Simons
> Eindhoven University of Technology
>
> Op 24-7-2011 1:54, Harvey P. Dale schreef:
>> 	What is the easiest and most efficient way to transform the
>> output from Reduce into a list of values?  For example, if Reduce
>> produces
>> (a==1001&&b==1001000)||(a==1002&&b==501000)||(a==1004=
>> &&b==251000) and I
>> want {{1001,1001000},{1002,501000},{1004,251000}}, what is the best way
>> to go from the former to the latter?
>>
>> 	Harvey
>>
>> Harvey P. Dale
>> University Professor of Philanthropy and the Law
>> Director, National Center on Philanthropy and the Law
>> 139 MacDougal Street
>> New York, N.Y. 10012-1076
>> Tel: 212-998-6161
>> Fax: 212-995-3149
>
>

```

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