Re: Table with conditions

• To: mathgroup at smc.vnet.net
• Subject: [mg119879] Re: Table with conditions
• From: Bob Hanlon <hanlonr at cox.net>
• Date: Mon, 27 Jun 2011 07:32:44 -0400 (EDT)
• Reply-to: hanlonr at cox.net

```Reduce[{-h <= k + 1 <= h, -h <= k <= h}, k]

(h == 1/2 && k == -(1/2)) || (h > 1/2 && -h <= k <= -1 + h)

%[[-1, -1]]

-h <= k <= -1 + h

In the Table, the iterator for k should be {k, -h, h-1}

Bob Hanlon

---- "J. Jesus Rico Melgoza" <jerico at umich.mx> wrote:

=============
I am constructing a Table

h=60
hi=60
P1 = Flatten[
Table[{Pk[k].Fl[l], k + l}, {k, -h,
h}, {l, -hi, hi}], 1]
This yields a table with two columns. First column contains vector of order n and column 2 contains an scalar
I want to add conditions to generate the elements in the Table
-h<=k+l<=h.
I do not know how to do this with the function Table[..] of Mathematica. I am asking for your help.
I do not want rows in my table that do not satisfy the condition.

Pk[k] is matrix and Fl[l] is a column vector

Thanks in advance

Jesus Rico-Melgoza

```

• Prev by Date: End of Sound
• Next by Date: NSolve...
• Previous by thread: Re: Table with conditions
• Next by thread: Re: Table with conditions