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MathGroup Archive 2011

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x/2 pr

  • To: mathgroup at smc.vnet.net
  • Subject: [mg123097] x/2 pr
  • From: afsinoglu <afsinoglu at gmail.com>
  • Date: Wed, 23 Nov 2011 07:06:37 -0500 (EST)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com

m> 2 for x / 2 Would not recognize the problem, help is

 I'm sorry my English is poor.

u[x_, 0] := 0
du[x_, m_] := D[u[x, m], x]
\[Chi][m_] := Piecewise[{{0, m < 2}, {1, m \[GreaterSlantEqual] 2}}]
u[x_, m_] := \[Chi][m] u[x, m - 1] + h*\!\(
\*SubsuperscriptBox[\(\[Integral]\), \(0\), \(a\)]\(\((du[x, m - 1] -
        1 + 2\ \((
\*UnderoverscriptBox[\(\[Sum]\), \(j = 0\), \(m - 1\)]\((u[
\*FractionBox[\(x\), \(2\)], j]\ u[
\*FractionBox[\(x\), \(2\)],
              m - 1 - j])\))\))\) \[DifferentialD]x\)\) /. a :> x



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