Re: average of the consecutive coin tosses
- To: mathgroup at smc.vnet.net
- Subject: [mg121979] Re: average of the consecutive coin tosses
- From: Peter Pein <petsie at dordos.net>
- Date: Fri, 7 Oct 2011 04:51:56 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <j6jobf$lv7$1@smc.vnet.net>
Am 06.10.2011 10:19, schrieb michael partensky:
> Hi.
>
> What are the better ways of doing what this guy does very inefficiently for
> the average of the consecutive coin tosses:
>
> tr = (flips = 1; (#/flips++) & /@ Accumulate[Table[toss, {1000}]]) // N);
>
> where
>
> toss= RandomInteger[];
>
> Thanks
> Michael
Hi Michael,
1.) generate the table with RandomInteger[]
2.) make use of the attribute Listable.
Divide the Table by the Range of integers:
tr = Accumulate[RandomInteger[1, 1000]]Range[1000]^(-1);
This is approximately 3.5 as fast as your approach.
Peter