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Re:Function Doesn't Evaluate Local Variables?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg124730] Re:Function Doesn't Evaluate Local Variables?
  • From: Ted Ersek <ersekt at md.metrocast.net>
  • Date: Fri, 3 Feb 2012 02:06:47 -0500 (EST)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • References: <000501cce199$a3b3d7a0$eb1b86e0$@md.metrocast.net>

Brentt wanted to make a function that returns a pure function. Below I provide  foo[n,new]  which is simpler than the example he used.

foo[n_,new_]:=With[{n1=n,nn=new},ReplacePart[#,n1->nn]&]


In[2]:= foo[Index, a Sin[x]]

Out[2]= ReplacePart[#1 ,Index->a Sin[x]]&


The next two examples show how you can use With to evaluate part of a held expression.

In[5]:= With[{y=2.3+1.5}, Hold[4+2^2+y-6/2]]

Out[5]=Hold[4 + 2^2 + 3.8 - 6/2]


In[6]:=  y=2.1+1.1;
        With[{y=y},Hold[4+2^2+y-6/2]]

Out[7]=Hold[4 + 2^2 + 3.2 - 6/2]

Ted Ersek
   See my Mathematica tips & tricks at
    http://www.verbeia.com/mathematica/tips/Tricks.html




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