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Re: Some assistance from seasoned users.

  • To: mathgroup at smc.vnet.net
  • Subject: [mg124930] Re: Some assistance from seasoned users.
  • From: Tomas Garza <tgarza10 at msn.com>
  • Date: Sun, 12 Feb 2012 05:06:13 -0500 (EST)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • References: <201202111135.GAA16372@smc.vnet.net>

I tried this:
In[12]:= Integrate[(Sin[x])^3/x^3, {x, 0, Infinity}]
Out[12]= (3 \[Pi])/8
Is this what you want?
-Tomas

> Date: Sat, 11 Feb 2012 06:35:51 -0500
> From: peter.livingston at cox.net
> Subject: Some assistance from seasoned users.
> To: mathgroup at smc.vnet.net
>
> Folks!
>
> 
>
> I have recently come to the pleasures of Mathematica from other popular but
> very expensive programming methods that I, as a retiree, cannot afford.
>
> 
>
> My specific question is this: why am I able to get Mathematica to do the
> complete integral of sin(x)/x, but it refuses to do any of the other types:
> specifically sin^3[x]/x or sin^3[x]/x^3 over the half interval from zero to
> infinity. (see page 449 of G & R  Table of Integrals).
>
> 
>
> It seems to suggest that throwing away my Gradshtein and Ryzhik is premature
> in spite of the claims in the Mathematica "Mathematics and Algorithms"
> manual.
>
> 
>
> Peter Livingston


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