Re: Some assistance from seasoned users.

*To*: mathgroup at smc.vnet.net*Subject*: [mg124930] Re: Some assistance from seasoned users.*From*: Tomas Garza <tgarza10 at msn.com>*Date*: Sun, 12 Feb 2012 05:06:13 -0500 (EST)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*References*: <201202111135.GAA16372@smc.vnet.net>

I tried this: In[12]:= Integrate[(Sin[x])^3/x^3, {x, 0, Infinity}] Out[12]= (3 \[Pi])/8 Is this what you want? -Tomas > Date: Sat, 11 Feb 2012 06:35:51 -0500 > From: peter.livingston at cox.net > Subject: Some assistance from seasoned users. > To: mathgroup at smc.vnet.net > > Folks! > > > > I have recently come to the pleasures of Mathematica from other popular but > very expensive programming methods that I, as a retiree, cannot afford. > > > > My specific question is this: why am I able to get Mathematica to do the > complete integral of sin(x)/x, but it refuses to do any of the other types: > specifically sin^3[x]/x or sin^3[x]/x^3 over the half interval from zero to > infinity. (see page 449 of G & R Table of Integrals). > > > > It seems to suggest that throwing away my Gradshtein and Ryzhik is premature > in spite of the claims in the Mathematica "Mathematics and Algorithms" > manual. > > > > Peter Livingston

**References**:**Some assistance from seasoned users.***From:*"peter livingston" <peter.livingston@cox.net>