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Re: Extensive replacement of trigonometric functions
*To*: mathgroup at smc.vnet.net
*Subject*: [mg125027] Re: Extensive replacement of trigonometric functions
*From*: andres <jarosham at gmail.com>
*Date*: Sat, 18 Feb 2012 06:26:41 -0500 (EST)
*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com
*References*: <jhldmn$ouo$1@smc.vnet.net>
So, you don't want Mathematica to evaluate the expression -Cos[\
[Theta] + (2 \[Pi])/3]?
Since -Cos[\[Theta] + (2 \[Pi])/3] = Sin[\[Theta] + \[Pi]/6], I assume
you want to format the output for visualization purposes, because both
expressions will give the same results. If this is the case, I would
take two approaches: either apply a Hold to the rhs of the rule, or
I'd use a rule of the type Sin[\[Theta]_ + \[Pi]/6] :> -cos[\[Theta] +
(2 \[Pi])/3], so that the inexistent function "cos" keeps unevaluated.
If then you want to evaluate the expression you can release the Hold
or define cos[\[Theta]_] := Cos[\[Theta]].
Hope it helps.
Andr=E9s
On Feb 17, 6:29 am, Mauro <pi... at hotmail.com> wrote:
> Hello to everybody.
>
> I have this problem: I would like to replace in a long expression all
> the occurrences of:
>
> Sin[\[Theta]_ + \[Pi]/6] and Sin[\[Theta]_ - \[Pi]/6]
>
> with respectively:
>
> -Cos[\[Theta] + (2 \[Pi])/3] and Cos[\[Theta] - (2 \[Pi])/3]
>
> (which actually are the same thing).
> Regretfully, the application of the rules:
>
> Sin[\[Theta]_ + \[Pi]/6] -> -Cos[\[Theta] + (2 \[Pi])/3]
> Sin[\[Theta]_ - \[Pi]/6] -> Cos[\[Theta] - (2 \[Pi])/3]
>
> results in a flop, since sine functions stubbornly appear again!
>
> Can you help me?
>
> Thank you in advance
>
> Mauro
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