Re: Sum of Products - Complete The Square

*To*: mathgroup at smc.vnet.net*Subject*: [mg126714] Re: Sum of Products - Complete The Square*From*: Andrzej Kozlowski <akozlowski at gmail.com>*Date*: Sat, 2 Jun 2012 05:41:48 -0400 (EDT)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*References*: <201205310651.CAA27227@smc.vnet.net>

On 31 May 2012, at 08:51, djmpark wrote: > Thanks for introducing/reminding us of SymmetricPolynomial and the > associated SymmetricReduction. SymmetricReduction is the high tech > generalization of complete the square. > > 3 x^2 + y^2 + 6 x y; > Total@SymmetricReduction[%, {x, y}] > > 2 y^2 + 3 (x + y)^2 1. This is not quite right: 3 x^2 + y^2 + 6 x y; Total@SymmetricReduction[%, {x, y}] -2 y^2 + 3 (x + y)^2 2. I don't see why this a "generalisation of complete the square". In fact, there is no well defined notion of completing the square for arbitrary quadratic expressions in two variables, e.g. this is another one: (1/3)*(3*x + Sqrt[3]*y)^2 + x*y*(6 - 2*Sqrt[3]) In any case, symmetric reduction is about symmetric polynomials and not about squares and it is based not on anything "high tech" but in fact on an extremely classical fact, (known as the fundamental theorem of symmetric functions: http://mathworld.wolfram.com/FundamentalTheoremofSymmetricFunctions.html) that gave rise to the subject of invariant theory, namely, that the ring of invariants of the symmetric group on n symbols acting on polynomials in n-variables is a polynomial ring in n-variables. These new variables are known as the elementary symmetric functions. The seeming relation with completing the square is quite incidental. The only reason why it looks this way is that the first elementary polynomial is the sum of the variables so if the expression is a quadratic you will get in it (x+y+=85)^2. But: Total[SymmetricReduction[(2 x + y)^2, {x, y}]] -4 x y - 3 y^2 + 4 (x + y)^2 A complete square was turned in to an incomplete one. One would hardly want to call this "completing the square" would one? Andrzej Kozlowski