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Re: Typesetting built-in functions without evaluating

  • To: mathgroup at smc.vnet.net
  • Subject: [mg126404] Re: Typesetting built-in functions without evaluating
  • From: Brentt <brenttnewman at gmail.com>
  • Date: Tue, 8 May 2012 04:08:58 -0400 (EDT)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • References: <CAFJC7XqOJE+wKdxKny7p65mO7_FHz1zBOvxv2xON2QjFSD5PHw@mail.gmail.com>

I was able to answer my own question. I discovered Defer.

On Mon, May 7, 2012 at 6:31 PM, Brentt <brenttnewman at gmail.com> wrote:

> Hello, I've been wrestling with mathematica trying to get it to typeset a
> partial derivative in traditiaonal form without evaluating it. The closest
> I've been able to come is having it output
>
> in[1]:=D[x,y] //TraditionalForm
> out[2]:=Hold[ *typesetted partial derivative here* ]
>
> So I can get the unevaluated partial derivative notation to output, but I
> can't do it without having the "Hold" mucking it up. How might one go about
> this? I've tried all kinds of complicated schemes, and I'm sure I could
> hack together some sort of output form that looks like a pd but that is
> actually not. But I figure there has to be a simpler solution that I'm
> missing.
>
> Also I've tried setting D to HoldAll. It doesn't work for some reason and
> I'm not sure why? Evaluation order is still a dark art to me despite having
> read that portion of the manual a few times (in my defense I'm not the
> sharpest tool in the shed).
>



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