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MathGroup Archive 2012

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Re: Typesetting built-in functions without evaluating


I also tried  Defer[D[r,{t,2}]] but instead of D[..] I used the Palette 
symbol for differentiating something twice....the output it gave  for the 
denominator was dt dt instead
of d^2 t.....how come???....if I insert 3, I get dt dt dt...etc...


thanks...jerry blimbaum....




-----Original Message----- 
From: Dave Snead
Sent: Wednesday, May 09, 2012 2:50 AM
To: mathgroup at smc.vnet.net
Subject: [mg126433] Re: Typesetting built-in functions without evaluating

Brentt--

Defer[D[x,y]]
will display the partial derivative in traditional form

--Dave Snead

-----Original Message----- 
From: Brentt
Sent: Tuesday, May 08, 2012 1:08 AM
To: mathgroup at smc.vnet.net
Subject: [mg126433] Typesetting built-in functions without evaluating


Hello, I've been wrestling with mathematica trying to get it to typeset a
partial derivative in traditiaonal form without evaluating it. The closest
I've been able to come is having it output

in[1]:=D[x,y] //TraditionalForm
out[2]:=Hold[ *typesetted partial derivative here* ]

So I can get the unevaluated partial derivative notation to output, but I
can't do it without having the "Hold" mucking it up. How might one go about
this? I've tried all kinds of complicated schemes, and I'm sure I could
hack together some sort of output form that looks like a pd but that is
actually not. But I figure there has to be a simpler solution that I'm
missing.

Also I've tried setting D to HoldAll. It doesn't work for some reason and
I'm not sure why? Evaluation order is still a dark art to me despite having
read that portion of the manual a few times (in my defense I'm not the
sharpest tool in the shed).






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