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Re: Numerical expression
- To: mathgroup at smc.vnet.net
- Subject: [mg128813] Re: Numerical expression
- From: "Massimo" <linusx++ at mail.com>
- Date: Wed, 28 Nov 2012 03:15:54 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Delivered-to: l-mathgroup@wolfram.com
- Delivered-to: mathgroup-newout@smc.vnet.net
- Delivered-to: mathgroup-newsend@smc.vnet.net
- References: <20121126042617.44760687B@smc.vnet.net> <k91u1k$5k8$1@smc.vnet.net>
"Dave Snead" <dsnead6 at charter.net> ha scritto nel messaggio
news:k91u1k$5k8$1 at smc.vnet.net...
> Adding the necessary parentheses:
> ((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) + (9 (3)^(1/2) + 4 (23)^(1/2))^(1/
> 3))/(3)^(1/2)
> this comes out to
> (2*(9*Sqrt[3] + 4*Sqrt[23])^(1/3))/Sqrt[3]
>
> (2*(9*Sqrt[3] + 4*Sqrt[23])^(1/3))/Sqrt[3]//N
> gives
> 3.76887
> So it's not 1.
Thank you all for your anwers.
I was wrong with a minus sign. The correct expression is:
((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) + (9 (3)^(1/2) - 4 (23)^(1/2))^(1/
3))/(3)^(1/2)
With the RealOnly package I get the Real result that I was searching for.
FullSimplify[((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) + (9 (3)^(1/2) -
4 (23)^(1/2))^(1/3))/(3)^(1/2)] == 1
Now I ask you how to get the same result using online WolframAlpha.
Thanks again.
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