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Re: Testing a random integer generator
*To*: mathgroup at smc.vnet.net
*Subject*: [mg130393] Re: Testing a random integer generator
*From*: Bill Rowe <readnews at sbcglobal.net>
*Date*: Mon, 8 Apr 2013 00:05:36 -0400 (EDT)
*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com
*Delivered-to*: l-mathgroup@wolfram.com
*Delivered-to*: mathgroup-newout@smc.vnet.net
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On 4/6/13 at 9:53 PM, c_mcinnis at hotmail.com (Clif McInnis) wrote:
>I am trying to test the random integer generator in a program to
>make sure that it gives the type of output that I am looking for. I
>expect it to generate (p<>q)<10 slightly less than 1/8 of the time
>and (p=q)<10 slightly more than 1/8 of the time, 9<(p<>q)<20
>slightly less than 3/8 of the time, and 9<(p=q)<20 slightly more
>than 3/8 of the time. Regardless of my expectations I would like to
>see how the numbers actually come out, and to that end was
>attempting to test the test the code, but I can not get it to
>generate (print) any numbers. I am sure that I have made an error
>somewhere in the code, but I can not find it and am not getting any
>error messages. Thank you for any and all help.
>Initialization :> ({x = 0, p = 0, q = 0})
The line above is the reason the code never prints a value. It
does not set x,p or q to 0. Look up RuleDelayed in the
documentation center. Change this to
x=0;
and your While loop will print values
>While[x < 100, {
>Clear[p, q],
the line above accomplishes nothing. It is not necessary in
Mathematica to clear variables before using them.
>q = RandomInteger[{1, 4}], If[q < 4,
>{p = RandomInteger[{10, 20}],
>q = RandomInteger[],
>If[q == 1, q = p, q = RandomInteger[{10, 20}]]}, {p = RandomInteger[{1, 9}],
>q = RandomInteger[],
>If[q == 1, q = p, q = RandomInteger[{1, 9}]]}], Print[p],
>Print[q]}; x++]
Note a better choice when you simply want to execute a section
of code n times is Do rather than While. The code below:
Do[
{q = RandomInteger[{1, 4}];
If[q < 4,
p = RandomInteger[{10, 20}]; q = RandomInteger[];
If[q == 1, q = p,
q = RandomInteger[{10, 20}]], {p = RandomInteger[{1, 9}],
q = RandomInteger[],
If[q == 1, q = p, q = RandomInteger[{1, 9}]]}], Print[p],
Print[q]}, {100}]
does exactly the same as your code without the need for x.
Also, Print sends its output to $Output. So, unless you redefine
$Output, you won't capture the results of your generator for
further analysis.
an efficient way to capture the output would be as follows:
output = {};
Do[
{q = RandomInteger[{1, 4}];
If[q < 4,
p = RandomInteger[{10, 20}]; q = RandomInteger[];
If[q == 1, q = p,
q = RandomInteger[{10, 20}]], {p = RandomInteger[{1, 9}],
q = RandomInteger[],
If[q == 1, q = p, q = RandomInteger[{1, 9}]]}],
output = {output, p, q}}, {100}]
This captures all of the p,q values in a nested list which can
be made into a simple list using Flatten. That is you can do
Histogram[Flatten@output]
to create a histogram of p,q values. Or
Mean[Flatten@output] to compute the mean value and so on.
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