Re: Sparse Array Question

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• Subject: [mg130585] Re: Sparse Array Question
• From: Sseziwa Mukasa <mukasa at gmail.com>
• Date: Wed, 24 Apr 2013 07:02:14 -0400 (EDT)
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```One idea:

#[[1, 1]] -> Total[#[[All, 2]]] & /@ Split[Sort[myList], #[[1]] == #2[[1]] &]

In versions 7 and later you can do:

#[[1, 1]] -> Total[#[[All, 2]]] & /@ GatherBy[myList, #[[1]] &]

On Apr 23, 2013, at 12:04 AM, christopher arthur <chris.arthur1 at gmail.com> wrote:

> Hello,
>
> I have a list of rules for defining a SparseArray.  The list has some
> coordinates repeated with different values.  If a coordinate appears in
> the list more than once, I want to sum up the values, and then have a
> SparseArray
>
> i.e., if my list were myList={{1,1}->1,{2,1}->2,{1,1}->3} then my
> SparseArray should have {1,1}->4.  I've tried using ReplacePart on an
> array to say myArray=ReplacePart[myArray,...] but this seems horribly
> inefficient as a way to change values in an array.
>
> I'm using Mathematica 5.2
>
> Cheers,
>
> Chris
>

```

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