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Re: parametric plot and filling


I would try to convert it to a standard plot.


ParametricPlot[
 {{2 t, -t^2}, {6 + 2 t, -t^2}},
 {t, -2, 2},
 Axes -> {True, False},
 Ticks -> None,
 PlotStyle -> {{Thick, Cyan}, {Thick, Green}}]


Plot[
 Evaluate[y /. {
    Solve[Thread[
      {x, y} == {2 t, -t^2}], {y, t}],
    Solve[Thread[
      {x, y} == {6 + 2 t, -t^2}], {y, t}]}],
 {x, -4, 10},
 Axes -> {True, False},
 Ticks -> None,
 PlotStyle -> {{Thick, Cyan}, {Thick, Green}},
 PlotRange -> {-4, 0},
 AspectRatio -> 0.285714,
 Filling -> -4]



Bob Hanlon




On Tue, Aug 20, 2013 at 7:36 AM, Francisco Gutierrez <fgutiers2002 at yahoo.com
> wrote:

>
> Dear group:
>
> DoesParametricPlot admit the Filling option? Seems it not? How then to
> perform it?
> Lokk at the following simple example:
>
> ParametricPlot[{{2 t,-t^2},{6+ 2 t,-t^2}}, {t,-2,2},Axes->{True,False},
> Ticks->None, PlotStyle->{{Thick,Cyan},{Thick,Green}}]
>
>
>
> The if I introduce the Filling command inside PlotStyle nothing happens,
> and outside it produces an error. Any ideas?
> francisco
>




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