MathGroup Archive 2013

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: sorting?


Many thanks Bob!

Francisco


________________________________
From: Bob Hanlon <hanlonr357 at gmail.com>
To: mathgroup at smc.vnet.net 
Sent: Saturday, January 26, 2013 4:58 PM
Subject: [mg129597] Re: sorting?

 lalista = {{0, 5}, {8, 8}, {2, 2}, {3, 5}, {1, 3}, {3, 9}};

SortBy[lalista, (Divide @@ #) + 10^-6*#[[2]] &] // Reverse

{{8, 8}, {2, 2}, {3, 5}, {3, 9}, {1, 3}, {0, 5}}


Bob Hanlon


On Sat, Jan 26, 2013 at 1:39 AM, Francisco Gutierrez
<fgutiers2002 at yahoo.com> wrote:

>
> Friends:
> I have a large list of simple numerical lists, and I want to sort it using two criteria. in the simplest case, suppose the sublists are of length two, and
> that my first criterion is the quotient of part one by part two, and my second criterion is the size of part two (no zeros in part 2.  I want to sort
> using the first criterion, and then break the ties using the second one.
> So for example if I had
> lalista={{0,5},{8,8},{2,2},{3,5},{1,3},{3,9}},
> the sorting should return
>
{8,8},{2,2},{3,5},{3,9},{1,3},{0,5}}
>
> Of course this can be done, but I wonder if it is a way to make this only with native Mathematica tools (wich is always far more efficient).

> Thanks for your help
> 
Francisco
>



  • Prev by Date: Re: Differentiating Interpolation Functions -- "Delaunay" Interpolation
  • Next by Date: Mathematica 9 IsotopeData is no longer self-consistent
  • Previous by thread: Re: sorting?
  • Next by thread: Re: sorting?