Re: sorting?
- To: mathgroup at smc.vnet.net
- Subject: [mg129597] Re: sorting?
- From: Francisco Gutierrez <fgutiers2002 at yahoo.com>
- Date: Mon, 28 Jan 2013 02:24:01 -0500 (EST)
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- Reply-to: Francisco Gutierrez <fgutiers2002 at yahoo.com>
Many thanks Bob! Francisco ________________________________ From: Bob Hanlon <hanlonr357 at gmail.com> To: mathgroup at smc.vnet.net Sent: Saturday, January 26, 2013 4:58 PM Subject: [mg129597] Re: sorting? lalista = {{0, 5}, {8, 8}, {2, 2}, {3, 5}, {1, 3}, {3, 9}}; SortBy[lalista, (Divide @@ #) + 10^-6*#[[2]] &] // Reverse {{8, 8}, {2, 2}, {3, 5}, {3, 9}, {1, 3}, {0, 5}} Bob Hanlon On Sat, Jan 26, 2013 at 1:39 AM, Francisco Gutierrez <fgutiers2002 at yahoo.com> wrote: > > Friends: > I have a large list of simple numerical lists, and I want to sort it using two criteria. in the simplest case, suppose the sublists are of length two, and > that my first criterion is the quotient of part one by part two, and my second criterion is the size of part two (no zeros in part 2. I want to sort > using the first criterion, and then break the ties using the second one. > So for example if I had > lalista={{0,5},{8,8},{2,2},{3,5},{1,3},{3,9}}, > the sorting should return > {8,8},{2,2},{3,5},{3,9},{1,3},{0,5}} > > Of course this can be done, but I wonder if it is a way to make this only with native Mathematica tools (wich is always far more efficient). > Thanks for your help > Francisco >
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- sorting?
- From: Francisco Gutierrez <fgutiers2002@yahoo.com>
- Re: sorting?
- From: Bob Hanlon <hanlonr357@gmail.com>
- sorting?