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Re: Definitions missing
*To*: mathgroup at smc.vnet.net
*Subject*: [mg131034] Re: Definitions missing
*From*: Bob Hanlon <hanlonr357 at gmail.com>
*Date*: Wed, 5 Jun 2013 03:28:21 -0400 (EDT)
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*References*: <20130604060024.165FA6A67@smc.vnet.net>
To see how it is calculated just give it some symbolic data:
len = 5;
data = Array[d, len];
mean = Mean[data];
$Assumptions = {Element[data, Reals]}; (* used with Simplify *)
s = StandardDeviation[data] // Simplify;
s == Sqrt[Total[(data - mean)^2]/(len - 1)] // Simplify
True
Also, read all of the provided documentation. After pressing F1,
Under "Tutorials" there is a link to "Basic Statistics" that gives the
detailed definition for variance and defines standard deviation as the Sqrt
of variance.
Under "Properties and Relations"; there are five different ways shown for
calculating the standard deviation of data:
"StandardDeviation is a scaled Norm of deviations from the Mean"
s == Norm[data - mean]/Sqrt[len - 1] // Simplify
True
"StandardDeviation is the square root of a scaled CentralMoment"
s == Sqrt[CentralMoment[data, 2] len/(len - 1)] //
Simplify
True
"StandardDeviation is a scaled RootMeanSquare of the deviations"
s == RootMeanSquare[data - mean] Sqrt[len/(len - 1)] //
Simplify
True
"StandardDeviation is the square root of a scaled Mean of squared
deviations"
s == Sqrt[Mean[(data - mean)^2] len/(len - 1)] //
Simplify
True
"StandardDeviation as a scaled EuclideanDistance from the Mean"
s == EuclideanDistance[data, Table[mean, {len}]]/
Sqrt[(len - 1)] // Simplify
True
Bob Hanlon
On Tue, Jun 4, 2013 at 2:00 AM, Dr. Wolfgang Hintze <weh at snafu.de> wrote:
> I'm sometimes missing a short path to the *definition* of a
> Mathematica function. Perhaps somebody here could give me a hint.
>
> Example: StandardDeviation
>
> I'm double clicking the keyword in the notebook, press F1 and arrive
> in the help browser which tells me that "StandardDeviation" is the
> standard deviation.
> Fine, I almost expected that. But now, how is this quantity defined?
> This is a simple example, of course, but I admit that I forget
> sometimes if it was the sum of the cuadratic differences or the square
> root of it, was it 1/n or 1/(n-1)?
>
> But the same holds for all functions which frequently are defined e.g.
> by power series or integrals. I personally would like to see this
> definition in the help browser.
>
> Sorry again for the perhaps trivial question.
>
> Regards,
> Wolfgang
>
>
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