[Date Index]
[Thread Index]
[Author Index]
Re: Making (a*\[Theta]11)/(1+a^2) into (a/(1+a^2))*\[Theta]11
*To*: mathgroup at smc.vnet.net
*Subject*: [mg131307] Re: Making (a*\[Theta]11)/(1+a^2) into (a/(1+a^2))*\[Theta]11
*From*: "djmpark" <djmpark at comcast.net>
*Date*: Wed, 26 Jun 2013 01:03:51 -0400 (EDT)
*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com
*Delivered-to*: l-mathgroup@wolfram.com
*Delivered-to*: mathgroup-outx@smc.vnet.net
*Delivered-to*: mathgroup-newsendx@smc.vnet.net
*References*: <31415507.250690.1372209487404.JavaMail.root@m06>
You have to use something like HoldForm and this may or may not interfere
with further calculation.
You could use:
a \[Theta]11/(1 + a^2);
% /. (r = Coefficient[%, \[Theta]11]) :>
HoldForm @@ {r} // TraditionalForm
a/(1+a^2) \[Theta]11
The TraditionalForm is necessary to get the desired order of the two
factors.
With the Presentations Application you could use:
<<Presentations`
a \[Theta]11/(1 + a^2) //
MapLevelParts[HoldForm, {{1, 2}}] // TraditionalForm
a/(1+a^2) \[Theta]11
And I'm sure you'll get a number of other answers.
David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/index.html
From: PiMan [mailto:kevingrady4 at gmail.com]
Hi, I have a formatting question.
In the output of an equation I am getting the term (a*\[Theta]11)/(1+a^2).
However, \[Theta]11 is the variable of interest here, and I would like the
term to be written as as a coefficient times \[Theta]11 and not include
\[Theta]11 in the ratio. That is, I would like the output to read
(a/(1+a^2))*\[Theta]11 instead. Does anyone have an idea of how I might be
able to do this? Thanks.
Prev by Date:
**Re: automatic grid**
Next by Date:
**Re: What is f[1]? Advanced question**
Previous by thread:
**Re: Decoupling E and I**
Next by thread:
**Making (a*\[Theta]11)/(1+a^2) into (a/(1+a^2))*\[Theta]11**
| |