Re: Solving non linear equations

*To*: mathgroup at smc.vnet.net*Subject*: [mg120022] Re: Solving non linear equations*From*: Norman Polozka <normanmath at gmail.com>*Date*: Tue, 5 Mar 2013 04:19:25 -0500 (EST)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-newout@smc.vnet.net*Delivered-to*: mathgroup-newsend@smc.vnet.net*References*: <20130304035816.A85396857@smc.vnet.net>

r is real always. parameter a can be changed but that is real too. Actually solving this equation is one step of my algorithm. On Tue, Mar 5, 2013 at 3:17 AM, Murray Eisenberg <murray at math.umass.edu>wrote: > Please use lower-case letters, such as 'a', instead of upper-case letters > for names you devise. (To avoid clashes with built-in Mathematica names, > all of which begin with '$' or else an upper-case letter.) Thus you should > use for your equation: > > x + 1/(1 + r^x) + a == 0 > > Are r and a supposed to be real, or would complex values be OK? What > range of values do you want for r or for a? > > What makes you think there is a solution? Have you tried plotting. Look, > e.g., at: > > > Manipulate[Plot[x+1/(1+r^x)+a,{x,-10,10},AxesOrigin->{0,0}],{{r,0},-10,10},{{a,0},-10,10}] > > > On Mar 3, 2013, at 10:58 PM, Norman Polozka <normanmath at gmail.com> wrote: > > > I want to solve such equation by using mathematica, > > > > Solve[x+1/(1+r^x)+A==0,x] > > > > But it says it can't solve. Any idea of solving such equations? > > --- > Murray Eisenberg murray at math.umass.edu > Mathematics & Statistics Dept. > Lederle Graduate Research Tower phone 413 549-1020 (H) > University of Massachusetts 413 545-2838 (W) > 710 North Pleasant Street fax 413 545-1801 > Amherst, MA 01003-9305 > > > > > >

**References**:**Solving non linear equations***From:*Norman Polozka <normanmath@gmail.com>