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Re: Solving non linear equations


r is real always. parameter a can be changed but that is real too. Actually
solving this equation is one step of my algorithm.

On Tue, Mar 5, 2013 at 3:17 AM, Murray Eisenberg <murray at math.umass.edu>wrote:

> Please use lower-case letters, such as 'a', instead of upper-case letters
> for names you devise. (To avoid clashes with built-in Mathematica names,
> all of which begin with '$' or else an upper-case letter.) Thus you should
> use for your equation:
>
>   x + 1/(1 + r^x) + a == 0
>
> Are r and a supposed to be real, or would complex values be OK?  What
> range of values do you want for r or for a?
>
> What makes you think there is a solution? Have you tried plotting. Look,
> e.g., at:
>
>
> Manipulate[Plot[x+1/(1+r^x)+a,{x,-10,10},AxesOrigin->{0,0}],{{r,0},-10,10},{{a,0},-10,10}]
>
>
> On Mar 3, 2013, at 10:58 PM, Norman Polozka <normanmath at gmail.com> wrote:
>
> >   I want to solve such equation by using mathematica,
> >
> > Solve[x+1/(1+r^x)+A==0,x]
> >
> > But it says it can't solve. Any idea of solving such equations?
>
> ---
> Murray Eisenberg                                    murray at math.umass.edu
> Mathematics & Statistics Dept.
> Lederle Graduate Research Tower            phone 413 549-1020 (H)
> University of Massachusetts                               413 545-2838 (W)
> 710 North Pleasant Street                         fax   413 545-1801
> Amherst, MA 01003-9305
>
>
>
>
>
>


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