Re: a simple question

*To*: mathgroup at smc.vnet.net*Subject*: [mg131729] Re: a simple question*From*: Murray Eisenberg <murray at math.umass.edu>*Date*: Tue, 24 Sep 2013 04:17:35 -0400 (EDT)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-outx@smc.vnet.net*Delivered-to*: mathgroup-newsendx@smc.vnet.net*References*: <20130924015950.56E2A6A52@smc.vnet.net>

Do you mean you want to solve that equation for h? (That's a different thing than "evaluating it", which would not be possible since the left hand side is not the sort of expression to which you can assign a value -- and what does is to assign a value. Whereas == denotes an equality.) Perhaps you mean something like the following: Solve[A Log[h]/h - x == 0, h] The result you'll get gives the solution as: h -> -((A*ProductLog[-(x/A)])/x This may or may not be of use to you, since ProductLog is a not an "elementary" function. Do A and x have some specific values? By the way, it's a bad idea to use names in Mathematica that are, or begin with, an upper-case letter -- because that risks confounding them with the names of built-in objects. On Sep 23, 2013, at 9:59 PM, Dhaneshwar Mishra <dhaneshwarmishra at gmail.com> wrote: > > I would like to evaluate A*Log[h]/h -x=0 for h, can any body help me doing so? > > I am beginner for Mathematica. --- Murray Eisenberg murray at math.umass.edu Mathematics & Statistics Dept. Lederle Graduate Research Tower University of Massachusetts 710 North Pleasant Street Amherst, MA 01003-9305

**References**:**a simple question***From:*Dhaneshwar Mishra <dhaneshwarmishra@gmail.com>