Speeding UP Indexing and Joining of Different Size Rectangular Matrixes
- To: mathgroup at smc.vnet.net
- Subject: [mg52414] Speeding UP Indexing and Joining of Different Size Rectangular Matrixes
- From: "Benedetto Bongiorno" <bbongiorno at attglobal.net>
- Date: Fri, 26 Nov 2004 01:04:53 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Fellow MathGroup,
I have been using Mathematica for financial analysis purposes and have been
developing note book programs for about 5 years.
My skills at this are self taught with help from Wolfram training and support.
The largest challenge has been the speed in the analysis of large data sets.
The following is an example of a routine that takes many hours.
PLEASE HELP AND SHOW HOW I CAN IMPROVE THE ROUTINE TO MAKE THE RUN TIME
SHORTER.
Equipment HP XP 3.24 processor 2 Gigs
Mathematica 5.01
Data set a= 257470 by 40, Mixed numeric and string fields, but each field
(column) is either or numeric or string
Data set b= 258705 by 5, All fields are numeric
Objective: RowJoin the rows from each data set that have the same ID field
in their corresponding column one.
Thank you and Happy Holidays
ROUTINE
Create Index By Invoice ID
firstCol=loc01[[1]];
lastCol =loc01[[1]];
aa = Transpose[Take[Transpose[a],{firstCol, lastCol}]];
Length[aa]
257470
firstCol=loc04[[1]];
lastCol =loc04[[1]];
bb = Transpose[Take[Transpose[b],{firstCol, lastCol}]];
Length[bb]
258705
idx=Intersection[aa,bb];
Length[idx]
257249
n=Length[idx]+1
257250
Locate Position Of Each Record In aTable
ans01={};
For[i=1,i<n,i++,
step1 = Position[aa,idx[[i]]];
AppendTo[ans01,step1]]
ans01=Flatten[ans01,1];
Locate Position Of Each Record In bTable
ans02={};
For[i=1,i<n,i++,
step1 = Position[bb,idx[[i]]];
AppendTo[ans02,step1]]
ans02=Flatten[ans02,1];
Extract a Records by Index
ans01 =Extract[currentBalance,ans01];
Dimensions[ans01]
Flatten If Not A Matrix
If[MatrixQ[ans01],ans01=ans01,ans01=Flatten[ans01,1]];
Dimensions[ans01]
Extract b Records by Index
ans02 =Extract[interestBalance,ans02];
Dimensions[ans02]
Flatten If Not A Matrix
If[MatrixQ[ans02],ans02=ans02,ans02=Flatten[ans02,1]];
Dimensions[ans02]
ans01=matsort[ans01,loc01[[1]]];
ans02=matsort[ans02,loc04[[1]]];
noteTerms=RowJoin[ans02,ans01];
Dimensions[noteTerms]
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