Re: Forcing a parameter to be integer when using 'Integrate'
- To: mathgroup at smc.vnet.net
- Subject: [mg67590] Re: Forcing a parameter to be integer when using 'Integrate'
- From: Bill Rowe <readnewsciv at earthlink.net>
- Date: Sat, 1 Jul 2006 05:12:37 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
On 6/30/06 at 4:14 AM, i.e.linington at sussex.ac.uk (Ian Linington)
wrote:
>I would like to solve the integral:
>>Integrate[E^((n*I)*x)/Sqrt[1 + a^2*Sin[x]^2], {x,0,2*Pi}]
>with n integer and a real and positive. The problem is that I don't
>know how to tell Mathematica about these conditions on a and n.
>If I explicitly assign an integer value for n (i.e. 4 in this
>example), Mathematica solves the integral:
>>Integrate[E^((4*I)*x)/Sqrt[1 + a^2*Sin[x]^2], {x,0,2*Pi}]
>(with a few conditions) and gives the output
There are a variety of ways to get Mathematica to suppress generation of assumptions. Probably what you want is to use Assuming or Assumptions,
i.e.
Assuming[{Element[n,Integers] a>0}, Integrate[...
or
Integrate[...., Assumptions->{Element[n, Integers], a>0}]
Note, I am assuming usage of Mathematica version 5.2 here. The function Assuming was not introduced until version 5.
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