Re: Average the same elements of the list
- To: mathgroup at smc.vnet.net
- Subject: [mg130870] Re: Average the same elements of the list
- From: Ray Koopman <koopman at sfu.ca>
- Date: Thu, 23 May 2013 04:04:37 -0400 (EDT)
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- Delivered-to: l-mathgroup@wolfram.com
- Delivered-to: mathgroup-outx@smc.vnet.net
- Delivered-to: mathgroup-newsendx@smc.vnet.net
datanew = {data[[1,1]], Mean@Pick[data[[All,2]],data[[All,1]],data[[1,1]]]}
----- BBabic <bipsich101 at gmail.com> wrote:
> Hello,
> I have list which is something like
> data={
> {{a1,b1,c1},d1},{{a2,b2,c2},d2}}
> I would like to get new list which gets average of the second elements if the first elements in the sublists are all the same.
> Namely if a1=a2,b1=b2,c1=c2
> new list would look like
> datanew={{a1,b1,c1},Mean[{d1,d2}]
> Is there an elegant way to do this ?
> Thanks!