Re: Wanted: a trick
- To: mathgroup at smc.vnet.net
- Subject: [mg3933] Re: Wanted: a trick
- From: rhall2 at umbc.edu (hall robert)
- Date: Fri, 10 May 1996 03:30:16 -0400
- Organization: University of Maryland, Baltimore County
- Sender: owner-wri-mathgroup at wolfram.com
In article <4m7q5d$k5h at dragonfly.wolfram.com>,
Robert Knapp <rknapp at wolfram.com> wrote:
>Jinchul Park wrote:
>> a = b = Exp[1 + 1.234 k] (k is a variable).
>> I want to find t by dividing a by b such as
>> 0. k
>> t = a/b. What I get is E. How come the result is NOT '1' ? In other
>> words, why '0. k' is not calculated as '0'?
>Mathematica keeps track of the difference between exact zeros (0) and
>inexact zeros (0.). Since inexact zeros may be the result of roundoff
>or other approximate number errors, they are not made to be equal to and
>exact zero by default.
>> Is there any way to make 0. k as 0?
>Yes, The simplest way to convert inexact zeros to exact zeros is with
>the command Chop:
>In:= a = b = Exp[1 + 1.234 k]
> 1 + 1.234 k
> 0. k
>> Also, in a simple symbolic calculation, 1.5 k - 1.5 k = '0. k' not '0.' On
>> the other hand, k - k = '0.' Would you tell me what I need to do to get
>> just '0' instead of '0. k'?
>In:= 1.5 k - 1.5 k
>Out= 0. k
Factor and Together also work. But Chop may cut more Gordian knots.
Bob Hall | "Know thyself? Absurd direction!
rhall2 at gl.umbc.edu | Bubbles bear no introspection." -Khushhal Khan Khatak
==== [MESSAGE SEPARATOR] ====
Prev by Date:
Operator overloading with Symbol tags: Correction!
Next by Date:
Re: Mathematica R^2 value
Previous by thread:
Wanted: a trick
Next by thread:
MathLink and Pascal ?