Re: Solving log equations, how?

*To*: mathgroup at smc.vnet.net*Subject*: [mg13635] Re: Solving log equations, how?*From*: Arnoud Buzing <arnoudb>*Date*: Thu, 06 Aug 1998 16:41:33 -0500*Organization*: Wolfram Research, Inc.*References*: <6qcqvq$qln$4@dragonfly.wolfram.com>*Sender*: owner-wri-mathgroup at wolfram.com

Jeffrey A. Soesbergen wrote: > > How can I solve the following exponential equations: > > 1. log3 x=-2 > > 2. log x + log (x+3) = 1 > > Can anyone tell me how to solve these in Mathematica? You can solve equations in Mathematica with the Solve[] command. It takes two arguments: the equation you want to solve and the variable you want to solve for. In your case the expressions to evaluate are: Solve[Log[3 x] == -2, x] (followed by shift-enter) Solve[Log[x] + Log[x + 3] == 1, x] (followed by shift-enter) You need to use == instead of = to indicate equality; the = is used for assignment. --- Arnoud