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Re: factor
*To*: mathgroup at smc.vnet.net
*Subject*: [mg30080] Re: [mg30063] factor
*From*: BobHanlon at aol.com
*Date*: Fri, 27 Jul 2001 03:52:17 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
In a message dated 2001/7/26 1:25:13 AM, norrey_h at hotmail.com writes:
>how can i solve a factor like (x^2 +1+ (1/2)^2) to get an answer (x+1)^2
>by using a mathematica.
>if i use a simplify function,the answer is 1/4 +x +x^2
>so what should i do to get a answer (x+1)^2.
(x^2 +1+ (1/2)^2)
x^2 + 5/4
Its factors would be complex
% == (x-I*Sqrt[5]/2)(x+I*Sqrt[5]/2)//Simplify
True
(x^2 +x+ (1/2)^2)//Factor
(1/4)*(2*x + 1)^2
(x^2+2x+1)//Simplify
(x + 1)^2
(x^2+2*a*x+a^2)//Simplify
(a + x)^2
Bob Hanlon
Chantilly, VA USA
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