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MathGroup Archive 2001

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Re: factor

  • To: mathgroup at smc.vnet.net
  • Subject: [mg30080] Re: [mg30063] factor
  • From: BobHanlon at aol.com
  • Date: Fri, 27 Jul 2001 03:52:17 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

In a message dated 2001/7/26 1:25:13 AM, norrey_h at hotmail.com writes:

>how can i solve a factor like (x^2 +1+ (1/2)^2) to get an answer (x+1)^2
>by using a mathematica.
>if i use a simplify function,the answer is 1/4 +x +x^2
>so what should i do to get a answer (x+1)^2.

(x^2 +1+ (1/2)^2)

x^2 + 5/4

Its factors would be complex

% == (x-I*Sqrt[5]/2)(x+I*Sqrt[5]/2)//Simplify

True

(x^2 +x+ (1/2)^2)//Factor

(1/4)*(2*x + 1)^2

(x^2+2x+1)//Simplify

(x + 1)^2

(x^2+2*a*x+a^2)//Simplify

(a + x)^2


Bob Hanlon
Chantilly, VA  USA


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