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MathGroup Archive 2003

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Re: a first-time user question

  • To: mathgroup at smc.vnet.net
  • Subject: [mg39427] Re: [mg39352] a first-time user question
  • From: "German Buitrago A." <gerbual at col2.telecom.com.co>
  • Date: Fri, 14 Feb 2003 03:24:43 -0500 (EST)
  • References: <200302120852.DAA14779@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

As y=x^(2/3) is equivalent to y^3=x^2, you can use:

<< "Graphics`ImplicitPlot`"

ImplicitPlot[y^3 == x^2,
  {x, -1, 1}]

Germán Buitrago A.
Manizales, Colombia

----- Original Message -----
From: "Ye Hu" <huye at wharton.upenn.edu>
To: mathgroup at smc.vnet.net
Subject: [mg39427] [mg39352] a first-time user question


> I have a simple (supposedly) question...
>
> I used the following command to draw a plot, but Mathematica could not run
> properly.
>
> Plot[x^(2/3),{x,-1,0}]
>
>
> I know the problem is about calculating (-1)^(1/3) in mathematica.
Although
> (-1)^(1/3) = -1,
> mathematica tries to calculate it numerically and gives complex results
> 0.5+0.8i
> How to solve this problem and restrict the solution to be only real
numbers?
>
> Thanks very much.
>
>
>



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