Re: a first-time user question

*To*: mathgroup at smc.vnet.net*Subject*: [mg39427] Re: [mg39352] a first-time user question*From*: "German Buitrago A." <gerbual at col2.telecom.com.co>*Date*: Fri, 14 Feb 2003 03:24:43 -0500 (EST)*References*: <200302120852.DAA14779@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

As y=x^(2/3) is equivalent to y^3=x^2, you can use: << "Graphics`ImplicitPlot`" ImplicitPlot[y^3 == x^2, {x, -1, 1}] Germán Buitrago A. Manizales, Colombia ----- Original Message ----- From: "Ye Hu" <huye at wharton.upenn.edu> To: mathgroup at smc.vnet.net Subject: [mg39427] [mg39352] a first-time user question > I have a simple (supposedly) question... > > I used the following command to draw a plot, but Mathematica could not run > properly. > > Plot[x^(2/3),{x,-1,0}] > > > I know the problem is about calculating (-1)^(1/3) in mathematica. Although > (-1)^(1/3) = -1, > mathematica tries to calculate it numerically and gives complex results > 0.5+0.8i > How to solve this problem and restrict the solution to be only real numbers? > > Thanks very much. > > >

**References**:**a first-time user question***From:*"Ye Hu" <huye@wharton.upenn.edu>