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Re: a first-time user question


As it has a cusp at x=0, better to write as
Plot[ {(x^2)^(1/3)},{x, -1, 1}]; 
as roots are reported in counter-clockwise direction 
with respect to x-axis in Argand diagram, try 
Re[-(1)^(1/3)] and Im[-(1)^(1/3)] to capture the real root.

> As y=x^(2/3) is equivalent to y^3=x^2, you can use:
>
> << 'Graphics`ImplicitPlot`'
>
> ImplicitPlot[y^3 == x^2,
>   {x, -1, 1}]
>
> Germán Buitrago A.
> Manizales, Colombia
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