Re: a first-time user question

*To*: mathgroup at smc.vnet.net*Subject*: [mg39448] Re: a first-time user question*From*: "Narasimham G.L." <google.news.invalid at web2news.net>*Date*: Sun, 16 Feb 2003 06:13:38 -0500 (EST)*References*: <200302120852.DAA14779@smc.vnet.net> <b2iav3$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

As it has a cusp at x=0, better to write as Plot[ {(x^2)^(1/3)},{x, -1, 1}]; as roots are reported in counter-clockwise direction with respect to x-axis in Argand diagram, try Re[-(1)^(1/3)] and Im[-(1)^(1/3)] to capture the real root. > As y=x^(2/3) is equivalent to y^3=x^2, you can use: > > << 'Graphics`ImplicitPlot`' > > ImplicitPlot[y^3 == x^2, > {x, -1, 1}] > > Germán Buitrago A. > Manizales, Colombia -- Posted via http://web2news.com To contact in private, remove

**References**:**a first-time user question***From:*"Ye Hu" <huye@wharton.upenn.edu>