Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2003
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2003

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: a first-time user question

  • To: mathgroup at smc.vnet.net
  • Subject: [mg39448] Re: a first-time user question
  • From: "Narasimham G.L." <google.news.invalid at web2news.net>
  • Date: Sun, 16 Feb 2003 06:13:38 -0500 (EST)
  • References: <200302120852.DAA14779@smc.vnet.net> <b2iav3$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

As it has a cusp at x=0, better to write as
Plot[ {(x^2)^(1/3)},{x, -1, 1}]; 
as roots are reported in counter-clockwise direction 
with respect to x-axis in Argand diagram, try 
Re[-(1)^(1/3)] and Im[-(1)^(1/3)] to capture the real root.

> As y=x^(2/3) is equivalent to y^3=x^2, you can use:
>
> << 'Graphics`ImplicitPlot`'
>
> ImplicitPlot[y^3 == x^2,
>   {x, -1, 1}]
>
> Germán Buitrago A.
> Manizales, Colombia
-- 
Posted via http://web2news.com
To contact in private, remove 




  • Prev by Date: Plotting problem
  • Next by Date: Re: a first-time user question
  • Previous by thread: Re: a first-time user question
  • Next by thread: Re: a first-time user question