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Re: a first-time user question

  • To: mathgroup at
  • Subject: [mg39449] Re: a first-time user question
  • From: "Narasimham G.L." < at>
  • Date: Sun, 16 Feb 2003 06:13:42 -0500 (EST)
  • References: <> <b2iav3$>
  • Sender: owner-wri-mathgroup at

As it has a cusp at x=0, better to write as
Plot[ {(x^2)^(1/3)},{x, -1, 1}]; 
as roots are reported in counter-clockwise direction 
with respect to x-axis in Argand diagram, try 
Re[-(1)^(1/3)] and Im[-(1)^(1/3)] to capture the real root.

> As y=x^(2/3) is equivalent to y^3=x^2, you can use:
> << 'Graphics`ImplicitPlot`'
> ImplicitPlot[y^3 == x^2,
>   {x, -1, 1}]
> Germán Buitrago A.
> Manizales, Colombia
Posted via
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