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MathGroup Archive 2004

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Re: Problem with graphics

  • To: mathgroup at
  • Subject: [mg45948] Re: [mg45897] Problem with graphics
  • From: Tomas Garza <tgarza01 at>
  • Date: Fri, 30 Jan 2004 04:16:39 -0500 (EST)
  • References: <>
  • Sender: owner-wri-mathgroup at

I'll give you a hint: try plotting Sqrt[x^2] in the interval {-1, 1}. It
gives you a symmetric plot! Why? Actually, Sqrt[x^2] is not equal to x, but

Tomas Garza
Mexico City

----- Original Message ----- 
From: "Lautaro Vergara" <lvergara at>
To: mathgroup at
Subject: [mg45948] [mg45897] Problem with graphics

> Dear people,
> I have found the following problem. I have ploted
> f[x_, y_] := Sqrt[(x^2 + y^2)^3]
> with Plot3D in order to see how it looks. Then I ploted f[x, 0] (which
> is x^3) between -1 and 1 and I got a symmetric plot. It seems that
> Mathematica plot the function Sqrt[x^6] or (x^2)^(3/2) and evaluate
> first the symmetric term (x^6 or x^2)...
> Does anyone knows what it happens and how can it be fixed?
> Thanks in advance!
> Lautaro Vergara

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