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Re: Problem with graphics

  • To: mathgroup at
  • Subject: [mg45930] Re: Problem with graphics
  • From: Jens-Peer Kuska <kuska at>
  • Date: Fri, 30 Jan 2004 04:15:56 -0500 (EST)
  • Organization: Universitaet Leipzig
  • References: <bvaojg$a0i$>
  • Reply-to: kuska at
  • Sender: owner-wri-mathgroup at


when you Plot[]

Sqrt[(x^2)^3] it is *not* x^3 it is
Abs[x]^3 because Sqrt[x^2] is Abs[x].

If you need the other parts of the Riemann-Surface
you should draw it an selet the one you like.


Lautaro Vergara wrote:
> Dear people,
> I have found the following problem. I have ploted
> f[x_, y_] := Sqrt[(x^2 + y^2)^3]
> with Plot3D in order to see how it looks. Then I ploted f[x, 0] (which
> is x^3) between -1 and 1 and I got a symmetric plot. It seems that
> Mathematica plot the function Sqrt[x^6] or (x^2)^(3/2) and evaluate
> first the symmetric term (x^6 or x^2)...
> Does anyone knows what it happens and how can it be fixed?
> Thanks in advance!
> Lautaro Vergara

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