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Re: Problem with graphics
*To*: mathgroup at smc.vnet.net
*Subject*: [mg45936] Re: [mg45897] Problem with graphics
*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>
*Date*: Fri, 30 Jan 2004 04:16:06 -0500 (EST)
*References*: <200401291034.FAA09688@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
On 29 Jan 2004, at 11:34, Lautaro Vergara wrote:
> Dear people,
>
> I have found the following problem. I have ploted
>
> f[x_, y_] := Sqrt[(x^2 + y^2)^3]
>
> with Plot3D in order to see how it looks. Then I ploted f[x, 0] (which
> is x^3) between -1 and 1 and I got a symmetric plot. It seems that
> Mathematica plot the function Sqrt[x^6] or (x^2)^(3/2) and evaluate
> first the symmetric term (x^6 or x^2)...
> Does anyone knows what it happens and how can it be fixed?
>
> Thanks in advance!
>
> Lautaro Vergara
>
The problem is that f[x,0] is not, as you think, x^3 but
In[2]:=
f[x, 0]
Out[2]=
Sqrt[x^6]
This means that
In[6]:=
f[-1,0]
Out[6]=
1
and not -1. This is not Mathematica's falut but the usual convention in
mathematics. I suppose what you want is:
f[x_, y_] := PowerExpand[Sqrt[(x^2 + y^2)^3]]
which will produce the graph you are asking for. However, I suggest you
carefully check tha tis really what you need for this contradicts the
usual conventions and looks rather dubious to me.
Andrzej Kozlowski
Chiba, Japan
http://www.mimuw.edu.pl/~akoz/
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