Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?
- To: mathgroup at smc.vnet.net
- Subject: [mg55814] Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?
- From: dh <dh at metrohm.ch>
- Date: Thu, 7 Apr 2005 05:09:53 -0400 (EDT)
- References: <email@example.com>
- Sender: owner-wri-mathgroup at wolfram.com
Hi Matt, Mathematica gives a direction. I makes sense to specify a direction by a unit vector (length==1); Sincerely, Daniel Matt wrote: > Hello, > This isn't particularly important probably, however, I am trying to > learn as much about Mathematica as possible, and I thought this might > shed some light on a 'Why Mathematica does this or that' principle. > > I'm working my way through 'The Mathematica Guidebook for > Programming' and on page 177, he gives an example as follows: > > In:= DirectedInfinity[1 + I] DirectedInfinity[I] > Out:= DirectedInfinity[-(1 - I)/sqrt(2)] > > That puzzled me a bit, so I decided to see what Mathematica would do > with just the first part: > > In:= DirectedInfinity[1 + I] > Out:= DirectedInfinity[(1 + I)/sqrt(2)] > > I realize that (1 + I)/sqrt(2) is in the same direction as (1 + I), but > why did Mathematica change it to the more 'strange' form? > > Thanks, > > Matt >