Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?

*To*: mathgroup at smc.vnet.net*Subject*: [mg55814] Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?*From*: dh <dh at metrohm.ch>*Date*: Thu, 7 Apr 2005 05:09:53 -0400 (EDT)*References*: <d3041u$ndm$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Hi Matt, Mathematica gives a direction. I makes sense to specify a direction by a unit vector (length==1); Sincerely, Daniel Matt wrote: > Hello, > This isn't particularly important probably, however, I am trying to > learn as much about Mathematica as possible, and I thought this might > shed some light on a 'Why Mathematica does this or that' principle. > > I'm working my way through 'The Mathematica Guidebook for > Programming' and on page 177, he gives an example as follows: > > In[39]:= DirectedInfinity[1 + I] DirectedInfinity[I] > Out[39]:= DirectedInfinity[-(1 - I)/sqrt(2)] > > That puzzled me a bit, so I decided to see what Mathematica would do > with just the first part: > > In[40]:= DirectedInfinity[1 + I] > Out[40]:= DirectedInfinity[(1 + I)/sqrt(2)] > > I realize that (1 + I)/sqrt(2) is in the same direction as (1 + I), but > why did Mathematica change it to the more 'strange' form? > > Thanks, > > Matt >