Re: DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?

*To*: mathgroup at smc.vnet.net*Subject*: [mg55815] Re: [mg55802] DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ?*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Thu, 7 Apr 2005 05:09:54 -0400 (EDT)*Reply-to*: hanlonr at cox.net*Sender*: owner-wri-mathgroup at wolfram.com

To normalize the direction to a unit vector. Abs[(1+I)/Sqrt[2]] 1 Bob Hanlon > > From: "Matt" <anonmous69 at netscape.net> To: mathgroup at smc.vnet.net > Date: 2005/04/06 Wed AM 03:11:59 EDT > To: mathgroup at smc.vnet.net > Subject: [mg55815] [mg55802] DirectedInfinity[1 + I], why does it get replaced by (1 + I)/(sqrt(2) ? > > Hello, > This isn't particularly important probably, however, I am trying to > learn as much about Mathematica as possible, and I thought this might > shed some light on a 'Why Mathematica does this or that' principle. > > I'm working my way through 'The Mathematica Guidebook for > Programming' and on page 177, he gives an example as follows: > > In[39]:= DirectedInfinity[1 + I] DirectedInfinity[I] > Out[39]:= DirectedInfinity[-(1 - I)/sqrt(2)] > > That puzzled me a bit, so I decided to see what Mathematica would do > with just the first part: > > In[40]:= DirectedInfinity[1 + I] > Out[40]:= DirectedInfinity[(1 + I)/sqrt(2)] > > I realize that (1 + I)/sqrt(2) is in the same direction as (1 + I), but > why did Mathematica change it to the more 'strange' form? > > Thanks, > > Matt > >