[Date Index]
[Thread Index]
[Author Index]
Re: question: re-organising equations
*To*: mathgroup at smc.vnet.net
*Subject*: [mg55264] Re: [mg55179] question: re-organising equations
*From*: yehuda ben-shimol <bsyehuda at gmail.com>
*Date*: Thu, 17 Mar 2005 03:31:34 -0500 (EST)
*References*: <200503161035.FAA23761@smc.vnet.net>
*Reply-to*: yehuda ben-shimol <bsyehuda at gmail.com>
*Sender*: owner-wri-mathgroup at wolfram.com
First, note that in Mathematica notation you should use
x==f[A,B,C,D] to define an equaltiy (unless you work with TradidionalForm)
So I will use that notation here.
you can use pattern matching
myRule = {x -> A, y -> B, z -> C, w -> D, A -> x, B -> y, C -> z, D -> w}
x==f[A,B,C,D]/.myRule
will yield
A == f[x, y, z, w]
as desired
yehuda
On Wed, 16 Mar 2005 05:35:54 -0500 (EST), OneTel
<david.hanson at student.unsw.edu.au> wrote:
>
>
> I have a set of simultaneous equations which are very long and so I will
> not include them here. They take the form of:
>
> x = f(A,B,C,D)
> y = f(A,B,C,D)
> z = f(A,B,C,D)
> w = f(A,B,C,D)
>
> I would like to re-organise these into the form:
>
> A = f(x,y,z,w)
> B = f(x,y,z,w)
> C = f(x,y,z,w)
> D = f(x,y,z,w)
>
> May I trouble you for some suggestions as to how this can be achieved?
>
> Thank you,
>
> David Hanson
> Research Postgraduate
> UNSW, Kensington 2052 NSW
>
>
Prev by Date:
**Re: GridLines**
Next by Date:
**Histogram and BinCounts inconsistency**
Previous by thread:
**question: re-organising equations**
Next by thread:
**Re: question: re-organising equations**
| |