Solve with dot products
- To: mathgroup at smc.vnet.net
- Subject: [mg70723] Solve with dot products
- From: Oliver Friedrich <xoliver.friedrich at tzm.dex>
- Date: Tue, 24 Oct 2006 02:24:43 -0400 (EDT)
Hallo, I have some difficulties with interpretation of a solution that Solve returns. In[2]:= Solve[a.b.c==d,a] From In[2]:= Solve::ifun: Inverse functions are being used by Solve, so some solutions may \ not be found. Out[2]= {{a\[Rule]InverseFunction[Dot,1,3][d,b,c]}} When I do that equation by hand I get something that I can't put into correspondence with the solution above. * means Inverse of a (a.b)*=b*.a* a.b.c=d |(_)* c*.b*.a*=d* |c. b*.a*=c.d* |b. a*=b.c.d* |(_)* a=d.c*.b* b and c are swapped compared to the Mathematica solution. 1) Where's my error? 2) What's the interpretation of such an InverseFunction expression, I don't get along the docu. 3) What's the z in InverseFunction[x,y,z][args] good for when I could count the number of arguments in args? Thanks a lot for your help -- Regards Oliver Friedrich My email has no x!