MathGroup Archive 2007

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Re: How to get sqrt(Year^2)===Year?

On May 9, 2007, at 4:33 AM, Hatto von Aquitanien wrote:

> If I have some expression which takes the square root of a square, it
> evaluates leaving the whole square root expression unchanged.
> Year == (Year^2)^(1/2)
> just returns what I entered when evaluated.
> Year == Year
> evaluates to True.
> How do I persuade Mathematica to evaluate the first expression  
> completely?

It is evaluating it completely, Year == (Year^2)^(1/2) is True only  
when Year is non-negative, so you have to tell Mathematica that  
that's the case:




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