MathGroup Archive 2007

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: How to get sqrt(Year^2)===Year?


On May 9, 6:49 pm, Hatto von Aquitanien <a... at AugiaDives.hre> wrote:
> If I have some expression which takes the square root of a square, it
> evaluates leaving the whole square root expression unchanged.
>
> Year == (Year^2)^(1/2)
>
> just returns what I entered when evaluated.
>
> Year == Year
>
> evaluates to True.
>
> How do I persuade Mathematica to evaluate the first expression completely?
> --http://www.dailymotion.com/video/x1ek5w_wtc7-the-smoking-gun-of-911-u...http://911research.wtc7.nethttp://vehme.blogspot.com
> Virtus Tutissima Cassis


In[1]:=  Simplify[ Sqrt[year^2], {year \[Element] Reals, year > 0} ]
Out[1]:= year



  • Prev by Date: Re: How to get sqrt(Year^2)===Year?
  • Next by Date: Re: Mathematica 6 Graphics Options
  • Previous by thread: Re: How to get sqrt(Year^2)===Year?
  • Next by thread: Re: How to get sqrt(Year^2)===Year?