Re: How to get sqrt(Year^2)===Year?

*To*: mathgroup at smc.vnet.net*Subject*: [mg75783] Re: How to get sqrt(Year^2)===Year?*From*: siewsk at bp.com*Date*: Thu, 10 May 2007 05:20:25 -0400 (EDT)*References*: <f1s1v4$fip$1@smc.vnet.net>

On May 9, 6:49 pm, Hatto von Aquitanien <a... at AugiaDives.hre> wrote: > If I have some expression which takes the square root of a square, it > evaluates leaving the whole square root expression unchanged. > > Year == (Year^2)^(1/2) > > just returns what I entered when evaluated. > > Year == Year > > evaluates to True. > > How do I persuade Mathematica to evaluate the first expression completely? > --http://www.dailymotion.com/video/x1ek5w_wtc7-the-smoking-gun-of-911-u...http://911research.wtc7.nethttp://vehme.blogspot.com > Virtus Tutissima Cassis In[1]:= Simplify[ Sqrt[year^2], {year \[Element] Reals, year > 0} ] Out[1]:= year