Re: v. 6, third argument to rectangle

*To*: mathgroup at smc.vnet.net*Subject*: [mg75937] Re: v. 6, third argument to rectangle*From*: rip pelletier <bitbucket at comcast.net>*Date*: Sun, 13 May 2007 05:59:44 -0400 (EDT)*References*: <f21e5e$6e7$1@smc.vnet.net> <200705111030.GAA08108@smc.vnet.net> <f23oii$mvm$1@smc.vnet.net>

In article <f23oii$mvm$1 at smc.vnet.net>, Andrzej Kozlowski <akoz at mimuw.edu.pl> wrote: > It's true that it works, but the fact that it works seems to be now > undocumented. Mathematica 5.2 documentation states: > > "In Rectangle[{a, a}, {a, a}, graphics], graphics can be any graphics > object." > > but there does not seem to be any such statement in 6.0 (?) > > Andrzej Kozlowski > > > rip pelletier wrote: > >> hi, > >> > >> thru 5.2 we could display, for example, 2 graphs side-by-side by > >> using a > >> third argument to Rectangle, the name of a graphics object. > >> > >> 6.0 tells me that i cannot call Rectangle with 3 arguments. (true, it > >> was a bit of a kludge, and in principle i approve of it going away, > >> but....) > >> > >> what is the replacement? > >> > >> thanks, > >> rip > >> > > > > well, thanks. your answer makes it clear that i have some debugging to do. i didn't post because the documentation changed; i posted because i got the error message "Rectangle called with 3 arguments; 1 or 2 arguments are expected." somehow it must not mean what it says. i also see that i forgot to say i am using a macintosh, OS X 10.4.9. since i was using dave park's drawgraphics package, i need to construct an example without the package. i'll get to it. given a choice between being productive or crawling thru shattered notebooks, i think i'll keep working for a while. vale, rip -- NB eddress is r i p 1 AT c o m c a s t DOT n e t

**References**:**Re: v. 6, third argument to rectangle***From:*Jens-Peer Kuska <kuska@informatik.uni-leipzig.de>