Mathematica 9 is now available
Services & Resources / Wolfram Forums / MathGroup Archive
-----

MathGroup Archive 2007

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: ListPlot: Choose segents to draw.

  • To: mathgroup at smc.vnet.net
  • Subject: [mg82364] Re: [mg82296] ListPlot: Choose segents to draw.
  • From: DrMajorBob <drmajorbob at bigfoot.com>
  • Date: Thu, 18 Oct 2007 04:59:45 -0400 (EDT)
  • References: <30676599.1192654613735.JavaMail.root@m35>
  • Reply-to: drmajorbob at bigfoot.com

Maybe this does what you intend:

n = 17;
mesh = Pi/35;
tbl = Table[{i, Cos[k i]}, {k, 1, n}, {i, 0, Pi/2, mesh}];

Clear[risers]
risers[points : {{_?NumericQ, _?NumericQ} ..}] :=
  Cases[Partition[points, 2,
    1], {{_?NumericQ, one_?NumericQ}, {_?NumericQ, two_?NumericQ}} /;
    two > one]
ListPlot[Flatten[risers /@ tbl, 1], PlotJoined -> True]

That's still a messy plot, but maybe with your data it won't be.

Bobby

On Wed, 17 Oct 2007 02:59:07 -0500, Nacho <ncc1701zzz at gmail.com> wrote:

> Hello all.
>
> Using Mathematica V6, I have several hundred lists to plot.
>
> They draw OK just with
>
> ListPlot[mytable, Joined->True,PlotRange->All]
>
> But several hundred plots are a mess. I'm only interested in the
> segments of each list that are increasing, that is, for every x(i),
> x(i)>x(i+1).
>
> Is there any set of options to ListPlot to make the descending
> segments invisible? Some kind of MeshShading to choose betweet
> Automatic and None depending of two consecutive values.
>
> If I have to create a new mytable, please bear in mind that the total
> length of the lists must remain equal.
>
> Thanks a lot for your help.
>
>
>



-- 

DrMajorBob at bigfoot.com


  • Prev by Date: Re: Mathematica 3DPlot Making Objects
  • Next by Date: Re: Palette for Units Conversion
  • Previous by thread: ListPlot: Choose segents to draw.
  • Next by thread: Re: ListPlot: Choose segents to draw.