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Re: Hypergeometric1F1 polynomial


> The polynomial form you are expecting (see In[1]) can be obtained by
> taking the series expansion about x == 0 to the order n (see In[2]).

Well, I can obtain it even without series expansion. For example, as

In[3]:= Hypergeometric1F1[-1, -2, 2 x]

Out[3]= 1 + x

The problem is that the answers given by Mathematica to the Sum problem, are 
not the same - they are not polynomials, with the series expansion, or 
without.

Alec 



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