Re: FFT in Mathematica

*To*: mathgroup at smc.vnet.net*Subject*: [mg93868] Re: FFT in Mathematica*From*: "sjoerd.c.devries at gmail.com" <sjoerd.c.devries at gmail.com>*Date*: Thu, 27 Nov 2008 05:32:50 -0500 (EST)*References*: <ggj7lm$jb0$1@smc.vnet.net>

Before I'm going to look into this any further: could you explain what you think is 'weird' with the plot? Do you know what ought to be the outcome of the transform? By the way, I forgot to mention that you may want to use the option FourierParameters -> {0, -2 Pi} in FourierTransform if you want f to be in Hertz. Cheers -- Sjoerd On Nov 26, 12:16 pm, Oliver <sch_oliver2... at yahoo.de> wrote: > Hallo Nasser, > many thanks for ur suggestions.. > > In 1/(4*(Pi*1*t) it is supposed to be 1 and not I but i just wrote 1 b= ecause the original equation is 1/(4*(Pi*Alpha*t) And Alpha is supposed to = be constant which is almost equal to 1. > > well, i took your solution and then plotted the Spectrum of it like this: > > Plot[Cosh[(1 + I)*Sqrt[f]*Sqrt[3*Pi]]/(2*Sqrt[3]*Pi) // Abs, {f, 0, > 1000}] > > But i still have the problem that the Plot looks unexcpected and weird. > Actually, my aim is to calculate the Spectrum Bandwidth, but i do not thi= nk that i can calculate the bandwidth of the resulted Plot because i do not= see any peaks. > or do u think it should be correct Plot?