Re: PolarPlot goes upto 1.2 on axis, not 1?
- To: mathgroup at smc.vnet.net
- Subject: [mg105128] Re: [mg105092] PolarPlot goes upto 1.2 on axis, not 1?
- From: Chris Poole <chris at chrispoole.com>
- Date: Sat, 21 Nov 2009 03:37:45 -0500 (EST)
- References: <23776586.1258717819053.JavaMail.root@n11>
Sorry about that,
This is the code:
PolarPlot[Sin[2 \[Theta]]^2, {\[Theta], -\[Pi]/2, \[Pi]/2},
PolarGridLines -> True, PolarAxes -> True,
PolarTicks -> {Table[i \[Degree], {i, -90, 90, 15}], Automatic},
PlotRange -> {{0, 2}, {-1, 1}}, PerformanceGoal -> "Speed",
PlotRangeClipping -> False,
PlotStyle -> {{Red, Thick, Dotted}, {Red, Thick}},
PlotLabel -> "label"]
The 'y' axis goes to 1.2; I'd like it to go to 1, and thus have the
plot peak at the outer bold line.
Thanks.
On Fri, Nov 20, 2009 at 1:12 PM, David Park <djmpark at comcast.net> wrote:
> Copy as Input Text and paste the explicit code into your posting. Otherwise
> you are asking responders to guess what you did.
>
>
> David Park
> djmpark at comcast.net
> http://home.comcast.net/~djmpark/
>
>
> From: fo3nix [mailto:chrispoole at gmail.com]
>
> Hi guys,
> I am trying to polarplot a function like Sin[2 x]^2, from -Pi/2 to Pi/
> 2, with polar ticks and gridlines enabled.
>
> Every time I do this, the vertical axis goes up to 1.2, not 1 --- is
> there any way to have this only go upto 1? (The function I'm plotting
> goes upto 1 only.)
>
> Cheers!
>
>
>