Re: PolarPlot goes upto 1.2 on axis, not 1?

*To*: mathgroup at smc.vnet.net*Subject*: [mg105128] Re: [mg105092] PolarPlot goes upto 1.2 on axis, not 1?*From*: Chris Poole <chris at chrispoole.com>*Date*: Sat, 21 Nov 2009 03:37:45 -0500 (EST)*References*: <23776586.1258717819053.JavaMail.root@n11>

Sorry about that, This is the code: PolarPlot[Sin[2 \[Theta]]^2, {\[Theta], -\[Pi]/2, \[Pi]/2}, PolarGridLines -> True, PolarAxes -> True, PolarTicks -> {Table[i \[Degree], {i, -90, 90, 15}], Automatic}, PlotRange -> {{0, 2}, {-1, 1}}, PerformanceGoal -> "Speed", PlotRangeClipping -> False, PlotStyle -> {{Red, Thick, Dotted}, {Red, Thick}}, PlotLabel -> "label"] The 'y' axis goes to 1.2; I'd like it to go to 1, and thus have the plot peak at the outer bold line. Thanks. On Fri, Nov 20, 2009 at 1:12 PM, David Park <djmpark at comcast.net> wrote: > Copy as Input Text and paste the explicit code into your posting. Otherwise > you are asking responders to guess what you did. > > > David Park > djmpark at comcast.net > http://home.comcast.net/~djmpark/ > > > From: fo3nix [mailto:chrispoole at gmail.com] > > Hi guys, > I am trying to polarplot a function like Sin[2 x]^2, from -Pi/2 to Pi/ > 2, with polar ticks and gridlines enabled. > > Every time I do this, the vertical axis goes up to 1.2, not 1 --- is > there any way to have this only go upto 1? (The function I'm plotting > goes upto 1 only.) > > Cheers! > > >