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Re: Simplify with NestedLessLess?


Why should it Simplify d? NestedLessLess has no built-in meaning. And even
if it did mean that b << a there is no reason that Mathematica should still
set b to zero. It doesn't even know if a and b are real positive. You will
have to set it to zero yourself.

d /. b -> 0  
a

For more complicated expressions you might have to use Limit.


David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/  



From: dbird [mailto:dbird at ieee.org] 

Please excuse if this has been answered before, but I can't find it.

Is there some way to do a Simplify with assumptions using a 
NestedLessLess or something similar? For example:

d=a+b
Simplify[d,NestedLessLess[a,b]]

Answer is:
a+b

Answer should be:
b

Thanks,

Dave




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