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Re: Simplify with NestedLessLess?
Why should it Simplify d? NestedLessLess has no built-in meaning. And even if it did mean that b << a there is no reason that Mathematica should still set b to zero. It doesn't even know if a and b are real positive. You will have to set it to zero yourself. d /. b -> 0 a For more complicated expressions you might have to use Limit. David Park djmpark at comcast.net http://home.comcast.net/~djmpark/ From: dbird [mailto:dbird at ieee.org] Please excuse if this has been answered before, but I can't find it. Is there some way to do a Simplify with assumptions using a NestedLessLess or something similar? For example: d=a+b Simplify[d,NestedLessLess[a,b]] Answer is: a+b Answer should be: b Thanks, Dave