Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
1998
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 1998

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Dimensions and Variables II

  • To: mathgroup at smc.vnet.net
  • Subject: [mg13736] Re: Dimensions and Variables II
  • From: Tobias Oed <tobias at physics.odu.edu>
  • Date: Wed, 19 Aug 1998 01:38:26 -0400
  • Organization: Old Dominion University
  • References: <6r1051$fib@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

naum at condor.physics.ucsb.edu wrote:
> 
>         I am starting to work on the variable problem.  I am woried that I
> wasn't clear enoughf in my news posting.  Here is simple version of the
> sort of  thing that I am doing.
> 
> f[x_]:=2x
> g[y_]:=3y
> h[z_]:=4z
> 
> a[x_,y_,z_]:=f+g+h
> b[x_,y_,z_]:=f*g*h
> 
> L[x_,y_,z_]:=a+b
> 
> Is there an easier way to do al this, like could I make V:={x,y,z} a
> list and  then just say L[V_]?  does every leval need the explit
> dependence declaration?   I have tried alot of things and none of then
> seem to work.
>         Thank You for any help you can give
>                 -NAUM

This may be a sollution (assuming you are interested in the dependency
of your functions on the original variables x,y and z)

f=2 x
g=3 y
h=4 z

a= f + g + h 
b= f * g * h

L=a+b

If you want the value of L[x=3,y=9,z=-1] you can use:

L /. {x->3,y->9,z->-1}

Tobias


  • Prev by Date: Re: unwrapping ArcTan
  • Next by Date: Re: Fourier Transform
  • Previous by thread: Re: Dimensions and Variables II
  • Next by thread: first usage of a button